Fwd: Re: [avr-gcc-list] efficiency of assigning bits

[Royce & Sharal Pereira]

Hello,
------- Forwarded message -------

> I am assuming these are equivalent.

Not quite. Do this:

PORTD &= ~(_BV(PD1) | _BV(PD4));

That will clear the two bits at the same time.
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or, PORTD &= ~((1<<1) | (1<<4)); //to bypass the _BV stuff,
or, PORTD &= ~(3<<1);
or, PORTD &= ~6; //cryptic but less typing.
or, PORTD &= 0xf9; //--ditto--
etc..etc..

--Royce.

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