Re: [Bug-apl] box and unbox that work uniformly and without exceptions

[Juergen Sauermann]

Hi Jay,

thanks, fixed in SVN 267.

/// Jürgen


On 05/14/2014 05:44 PM, Jay Foad wrote:
> That's because of a bug in GNU APL:
>
>        x←(1 2)(3 4)
>        (a b)←x
>        a≡1 2
> 0
>
> :-(
>
> Jay.
>
> On 14 May 2014 15:24, Blake McBride <address@hidden> wrote:
> > Your unbox doesn't work.  The following does:
> >
> > (s r)←⊃x ⋄ z←(⊃s)⍴⊃r
> >
> >
> > On Wed, May 14, 2014 at 3:43 AM, Jay Foad <address@hidden> wrote:
> > > On 13 May 2014 15:00, Blake McBride <address@hidden> wrote:
> > > > Here are the functions, examples to follow:
> > > >
> > > >        ∇box[⎕]∇
> > > > [0] z←box x
> > > > [1] z←⊂(⊂⍴x),⊂,x
> > > >
> > > >        ∇unbox[⎕]∇
> > > > [0] z←unbox x
> > > > [1] z←(⊃x[⎕IO])⍴⊃(x←⊃x)[⎕IO+1]
> > > FYI you can write your box as: z←⊂(⍴x)(,x)
> > > and unbox as: (s r)←⊃x ⋄ z←s⍴r
> > >
> > > Jay.