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From: | Elias Mårtenson |
Subject: | Re: [Bug-apl] IOTA |
Date: | Thu, 3 Mar 2016 16:12:44 +0800 |
Right. Here's a variation on Elias's solution that gets IOTA ⍬ right,
but doesn't handle the singleton cases correctly!
IOTA ← {⊃∘.,/(⍳¨⍵),⊂⊂⍬}
On 3 March 2016 at 01:08, Nick Lobachevsky <address@hidden> wrote:
> There is at least one other degenerate case, namely the "legacy"
> singleton, or one element vector. With a scalar argument, monadic
> iota returns a result depth one. With a vector argument, iota returns
> a result depth two. Except when there is only one element.
>
> ≡⍳⍳0 ⍝ can't find zilde
> 2
> ≡⍳⍳1 ⍝ singleton vector case returns result depth one
> 1
> ≡⍳,1
> 1
> ≡⍳,2
> 1
> ≡⍳,42
> 1
> ≡⍳(15⍴1)⍴1 ⍝ matrix singleton thankfully fails
> RANK ERROR
> ≡⍳⍳2
> 2
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