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Missing character when using ${VAR:1} and length(VAR)==1
From: |
Lauffher, Wolfgang |
Subject: |
Missing character when using ${VAR:1} and length(VAR)==1 |
Date: |
Thu, 20 Sep 2007 13:13:24 +0200 |
From: root
Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: linux
Compiler: gcc -I/usr/src/packages/BUILD/bash-3.1
-L/usr/src/packages/BUILD/bash-3.1/../readline-5.1
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='x86_64'
-DCONF_OSTYPE='linux' -DCONF_MACHTYPE='x86_64-suse-linux' -DCONF_VENDOR='suse'
-DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL -DHAVE_CONFIG_H -I.
-I. -I./include -I./lib -O2 -fmessage-length=0 -Wall -D_FORTIFY_SOURCE=2 -g
-D_GNU_SOURCE -DRECYCLES_PIDS -Wall -pipe -g -fbranch-probabilities
uname output: Linux erunb001 2.6.16.46-0.12-smp #1 SMP Thu May 17 14:00:09 UTC
2007 x86_64 x86_64 x86_64 GNU/Linux
Machine Type: x86_64-suse-linux
Bash Version: 3.1
Patch Level: 17
Release Status: release
Description:
there is missing a charachter when using the following:
# TT="oo"; echo "l${TT:1}l"
lol
# TT="o"; echo "l${TT:1}l"
l
Repeat-By:
every time
Fix:
In older versions it worked :-) also in 3.0.16
regards,
Wolfgang Lauffher
- Missing character when using ${VAR:1} and length(VAR)==1,
Lauffher, Wolfgang <=
- Message not available