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error in expression evaluation
From: |
Bernhard Bablok |
Subject: |
error in expression evaluation |
Date: |
Fri, 22 Feb 2008 12:48:01 +0100 |
User-agent: |
KMail/1.9.6 (enterprise 20070904.708012) |
Configuration Information [Automatically generated, do not change]:
Machine: i586
OS: linux-gnu
Compiler:
gcc -I/usr/src/packages/BUILD/bash-3.2
-L/usr/src/packages/BUILD/bash-3.2/../readline-5.2
Compilation
CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i586' -DCONF_OSTYPE='linux-gnu'
-DCONF_MACHTYPE='i586-suse-linux-gnu' -DCONF_VENDOR='suse'
-DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL -DHAVE_CONFIG_H -I.
-I. -I./include -I./lib -O2 -march=i586 -mtune=i686 -fmessage-length=0 -Wall
-D_FORTIFY_SOURCE=2 -fstack-protector -g -D_GNU_SOURCE -DRECYCLES_PIDS -Wall
-pipe -g -fPIE -fprofile-use
uname output: Linux sirius 2.6.22.9-0.4-default #1 SMP 2007/10/05 21:32:04 UTC
i686 athlon i386 GNU/Linux
Machine Type: i586-suse-linux-gnu
Bash Version: 3.2
Patch Level: 25
Release Status: release
Description:
The following code produces an error (second if-statement):
#!/bin/bash
if [ '(' != ',' ]; then
echo "'(' != ',' works :-)"
fi
if [ 'a' != 'b' -a '(' != ',' ]; then
echo "'a' != 'b' -a '(' != ',' does not work :-("
fi
It seems that the parser does not like the "(" after an "-a" in a compound
expression.
Repeat-By:
[Describe the sequence of events that causes the problem
to occur.]
Fix:
Workaround: don't use a compound expression, use a second if-statement within
the first if-statement.
Bernhard
- error in expression evaluation,
Bernhard Bablok <=