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"break" inside a while-condition
From: |
Philippe Wang |
Subject: |
"break" inside a while-condition |
Date: |
Tue, 11 Sep 2012 16:40:41 +0200 |
Configuration Information [Automatically generated, do not change]:
Machine: i386
OS: darwin12.0.0
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i386'
-DCONF_OSTYPE='darwin12.0.0' -DCONF_MACHTYPE='i386-apple-darwin12.0.0'
-DCONF_VENDOR='apple' -DLOCALEDIR='/alien/share/locale' -DPACKAGE='bash'
-DSHELL -DHAVE_CONFIG_H -DMACOSX -I. -I. -I./include -I./lib -I./lib/intl
-I/Users/phil/gnuutils/bash-4.2/lib/intl -g -O2
uname output: Darwin mba.local 12.1.0 Darwin Kernel Version 12.1.0: Tue Aug 14
13:29:55 PDT 2012; root:xnu-2050.9.2~1/RELEASE_X86_64 x86_64
Machine Type: i386-apple-darwin12.0.0
Bash Version: 4.2
Patch Level: 0
Release Status: release
Description:
"break" keyword inside a while-condition doesn't work as expected : it breaks
the wrong loop.
Repeat-By:
# 1) should raise a parsing error (but it doesn't)
while break ; true ; do true ; done
# 2) should break the outer loop (but it doesn't)
while true ; do while break ; do whatever-because-never-reached ; done ; echo
fail ; done
Fix:
I don't know.
- "break" inside a while-condition,
Philippe Wang <=