Re: [bug-gawk] float conversion

[Andreas Mueller]

Hi,

Andrew J. Schorr wrote:
> Hi,
> 
> On Thu, Oct 10, 2013 at 06:45:14PM +0200, Andreas Mueller wrote:
> > $ gawk 'BEGIN { for (i = -1; i <= 1; i += 0.1) { print "int("i") = " 
> > int(i)} }'
> 
> By default, gawk stores numbers in IEEE floating-point representation.
> Does this clarify what's going on?
After some looking into it again it suddenly does.

> ...
> If you want true fixed-point arithmetic, you should probably simulate it using
> integers:
v> 
> bash-4.1$ gawk 'BEGIN { for (i = -10; i <= 10; i += 1) { print "int("i/10") = 
> " int(i/10)} }'

Thanks, I'll keep that in mind.

What bothered me was that 'print i' would show "1" in the final iteration while 
'printf("%d\n", i)' and 'print int(i)' would show "0". But apparently it's 
because of OFMT.

Thanks and regards,
Andreas