Re: [bug-gawk] Why the length(seps) is one more than the return value of patsplit()?

[arnold]

Peng Yu <address@hidden> wrote:

> Hi,
>
> The following code shows that the length(seps) is one more than the
> return value of patsplit(). I thought that seps should have the same
> as the number of elements in "a". Why it is not the case? Could
> anybody help me understand this? Thanks.
>
> ~$ awk 'BEGIN { print patsplit("aAbBcC", a, /[a-z]/, seps); print
> seps[1], seps[2], seps[3], length(seps); }'
> 3
> A B C 4
>
> -- 
> Regards,
> Peng

Hi. Thanks for the report.  The fourth element is the null string. This
may be a bug. I need to review the code and work with it a bit.  I'll
reply again when I have more information.

THanks,

Arnold