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[bug-gawk] gawk debugger omits watchpoint


From: Hermann Peifer
Subject: [bug-gawk] gawk debugger omits watchpoint
Date: Wed, 25 Nov 2015 20:37:36 +0100
User-agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.10; rv:38.0) Gecko/20100101 Thunderbird/38.3.0

Hi again,

Below some sample code where it looks like the second watchpoint is not
reached before exiting. This looks wrong to me.

Hermann

$ printf "END{x=1;y=2}\n" > tmp.awk
$ printf "w x\nw y\nr\nc\n" | gawk -D -f tmp.awk /dev/null
Watchpoint 1: x
Watchpoint 2: y
Starting program:
Stopping in END ...
Watchpoint 1: x
  Old value: untyped variable
  New value: 1
main() at `tmp.awk':1
1       END{x=1;y=2}
Program exited normally with exit value: 0
$



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