Re: [bug-gawk] Is -M enabled by default?

[Peng Yu]

> gawk -e 'BEGIN{ x = 1; for(i=1;i<1000;++i) { x = x * 2; printf("%4d  %.3e\n", 
> i, x)} }'

The above code does not prove x is stored as double, because even if x
is stored as an arbitrary precision integer, it still can be converted
to double and printed with %e. Is there a way to print the underlying
type of a variable in awk. Thanks.

> All of those numbers are exactly representable in awk's default of C
> type double, which on modern machines in a 64-bit binary (base-2)
> format with a range of about 2.22E-308 to 1.79e+308.

-- 
Regards,
Peng