Re: operation of 'round' function

[David Kastrup]

"Eli Zaretskii" <eliz@is.elta.co.il> writes:

> > From: David.Kastrup@t-online.de (David Kastrup)
> > Date: 08 Feb 2002 11:35:28 +0100
> > 
> > >     Rounding a value equidistant between two integers may choose the
> > >     integer closer to zero, or it may prefer an even integer, depending on
> > >     your machine.  For example, \(round 2.5\) can return 3 on some
> > >     systems, but 3 on others.
> > 
> > You mean, it can return 3 on some systems and 2 on others.
> 
> Yes ;-)
> 
> > Apart from
> > which almost *no* machine will choose the integer *closer* to zero
> > when rounding.  Those machines not rounding to even will round *away*
> > from zero in almost all cases.
> 
> See the message by Andreas: it happens on Windows, because the
> fallback method is used.

See the message by Andreas: it does not happen on Windows because the
fallback method is used.

The fallback rounds towards infinity, *not* towards zero.

-- 
David Kastrup, Kriemhildstr. 15, 44793 Bochum
Email: David.Kastrup@t-online.de