bug#4891: 23.1; shell-command overwrites whole buffer

[Kevin Rodgers]

Stefan Monnier wrote:
> > Thanks for the quick reply!  Yes, that does make more sense now - but
> > what if I want to asynchronously insert output into an existing
> > buffer?
>
> Then switch to that buffer before starting the command and pass t as the
> OUTPUT-BUFFER.

But why is the distinction between append and replace conflated with the
OUTPUT-BUFFER argument in the first place?

--
Kevin Rodgers
Denver, Colorado, USA