Re: gawk version 3.1.0 will not print a ";"

[Aharon Robbins]

Greetings again.  Re:

>       gawk '{print "Input = "$_" ; "}' tmp

My previous note explained the problem.  The following
patch makes things work better, although I'm not 100%
convinced it's The Right Thing.  In any case, it should
solve your immediate problem.

You will need to rebuild from source, either by loading the
Redhat SRPM, or downloading source from ftp.gnu.org.

Good luck,

Arnold Robbins

*** ../gawk-3.1.0/awkgram.y     Mon Apr 23 10:25:58 2001
--- awkgram.y   Wed Jan 23 14:45:51 2002
***************
*** 1816,1822 ****
                exit(1);
        }
  
!       if (! do_traditional && c == '_') {
                if ((c = nextc()) == '"') {
                        intlstr = TRUE;
                        goto string;
--- 1959,1979 ----
                exit(1);
        }
  
!       /*
!        * Lots of fog here.  Consider:
!        *
!        * print "xyzzy"$_"foo"
!        *
!        * Without the check for ` lasttok != '$'' ', this is parsed as
!        *
!        * print "xxyzz" $(_"foo")
!        *
!        * With the check, it is "correctly" parsed as three
!        * string concatenations.  Sigh.  This seems to be
!        * "more correct", but this is definitely one of those
!        * occasions where the interactions are funny.
!        */
!       if (! do_traditional && c == '_' && lasttok != '$') {
                if ((c = nextc()) == '"') {
                        intlstr = TRUE;
                        goto string;