Re: AWK problem finding backslash

[Andreas Schwab]

"Joe Kolman" <address@hidden> writes:

> if (len10 >= 41) {sub("\\","",old_value); printf("\nentered len10")}

"\\" represents an incomplete regexp.  After stripping the quoting for a
string literal the resulting regexp contains a single backslash, which is
a quoting character in the regexp language.  To match a backslash you need
to quote it with a backslash, which, after adding the necessary quoting
for a string literal, becomes "\\\\".  Note that there are two levels of
quoting, one level for the string syntax and one level for the regexp
syntax, and both are using the same quoting character, the backslash.

Andreas.

-- 
Andreas Schwab, SuSE Labs, address@hidden
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