Re: Tr: Problem with grep v2.5.1

[Micah Cowan]

Paul Jarc wrote:
> Simon Nieux <address@hidden> wrote:
>>>     grep -B 3 "\.\.\.[0-9]\{3\}" wget.log | grep -v -B 3 "\.\.\.200"
> 
> That means that th second grep will print every line that doesn't
> match "\.\.\.200", and the three lines preceding each of those lines.
> To get what you want using grep, you'd need a different pattern in
> place of "\.\.\.[0-9]\{3\}" that inherently excludes "...200" without
> using -v:
> grep -E -B 3 '\.\.\.([013-9][0-9]{2}|2[1-9][0-9]|20[1-9])'

You're using -E, so it should be "..." rather than "\.\.\."

Won't this approach have /exactly/ the same behavior?

-- 
Micah J. Cowan
Programmer, musician, typesetting enthusiast, gamer...
http://micah.cowan.name/