Re: sed 4.2.1 bug

[Sophia Jacob]

Oh! ok.
Thank you very much!!

Sophia

On 7/11/12, Davide Brini <address@hidden> wrote:
> On Tue, 10 Jul 2012 22:31:32 +0530, Sophia Jacob <address@hidden>
> wrote:
>
>> Thank you very much Paolo!
>>
>> Still it looks like 'D' is not working at all in this case. I ran this:
>> $ sed -n '=;i\
>> ----
>> ;p;H;4,${g;i\
>> +++
>> ;=;D;h}' c    # c is the same file that contains 5 lines 1\n2\n3\n4\n5
>>
>> (Print the pattern space at the beginning of the command. So, if 'D'
>> deletes the first segment of the pattern space (which will contain
>> "1\n2\n3\n4\n", in the next itteration, 'p' should be printing
>> "2\n3\n\4". But it keeps printing "1\n2\n3\n4"!
>
> At line 4 the hold space (which is copied to the pattern space by the "g"
> command) contains
>
> \n1\n2\n3\n4
>
> note the leading \n. This, the "D" command only deletes the first \n,
> leaving 1\n2\n3\n4.
>
>
> --
> D.
>