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[bug #30895] match across line using grep can be successful only if user
From: |
Zhang Weiwu |
Subject: |
[bug #30895] match across line using grep can be successful only if user unset $LANG |
Date: |
Sat, 28 Aug 2010 01:45:43 +0000 |
User-agent: |
Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.2.3) Gecko/20100423 Ubuntu/10.04 (lucid) Firefox/3.6.3 Mnenhy/0.8.2 |
URL:
<http://savannah.gnu.org/bugs/?30895>
Summary: match across line using grep can be successful only
if user unset $LANG
Project: grep
Submitted by: zhangweiwu
Submitted on: Sat Aug 28 01:45:43 2010
Category: None
Severity: 3 - Normal
Item Group: None
Status: None
Privacy: Public
Assigned to: None
Open/Closed: Open
Discussion Lock: Any
_______________________________________________________
Details:
reproduced on Ubuntu 10.04 LTS:
address@hidden:~$ locale
LANG=zh_CN.UTF-8
LANGUAGE=zh_CN:zh
LC_CTYPE="zh_CN.UTF-8"
LC_NUMERIC="zh_CN.UTF-8"
LC_TIME="zh_CN.UTF-8"
LC_COLLATE="zh_CN.UTF-8"
LC_MONETARY="zh_CN.UTF-8"
LC_MESSAGES="zh_CN.UTF-8"
LC_PAPER="zh_CN.UTF-8"
LC_NAME="zh_CN.UTF-8"
LC_ADDRESS="zh_CN.UTF-8"
LC_TELEPHONE="zh_CN.UTF-8"
LC_MEASUREMENT="zh_CN.UTF-8"
LC_IDENTIFICATION="zh_CN.UTF-8"
LC_ALL=
address@hidden:~$ printf 'a\nb\0'| grep -z 'a.*b'
address@hidden:~$ export LANG=
address@hidden:~$ printf 'a\nb\0'| grep -z 'a.*b'
a
b
In the above case, grep -z 'a.*b' cannot successfully match as it should, but
if user unset $LANG, it can.
expected:
In all locales, grep should be able to match across lines using -z. This
command should always produce output:
printf 'a\nb\0'| grep -z 'a.*b'
_______________________________________________________
Reply to this item at:
<http://savannah.gnu.org/bugs/?30895>
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- [bug #30895] match across line using grep can be successful only if user unset $LANG,
Zhang Weiwu <=