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Re: [Bug-wget] what is the correct way to pass authentication informati


From: Norman Khine
Subject: Re: [Bug-wget] what is the correct way to pass authentication information
Date: Wed, 17 Feb 2010 20:38:30 +0100

On Wed, Feb 17, 2010 at 7:09 PM, Micah Cowan <address@hidden> wrote:
> Norman Khine wrote:
>> hello,
>> i can download the page using:
>>
>> $ wget http://username:address@hidden/file.html
>>
>> but when i try to convert the links and download all the images it
>> doesn't work and i get an error.
>>
>> HTTP request sent, awaiting response... 401 Authorization Required
>> Authorization failed.
>>
>> what is the correct way to pass authentication information and
>> download all the files for each url that is in my url.txt file
>>
>> -p --convert-links -i ../url.txt
>
> That method should work, though --user and --password are the preferred
> method.
>
> Perhaps username and/or password contain special characters that would
> need to be percent-encoded?

i did this, and it worked well

wget -m -U "Mozilla/5.0 (compatible; Konqueror/3.2; Linux)"
--http-user=USERNAME --http-password=PASSWORD -r -p -nH -nd -Pdownload
--wait=2 -k -i ../url.txt

but i still can't get to download the images, css and js files and
rewrite the downloaded page so that i can use it locally.

i have the '-p' switch also i have tried

with

--convert-links -r

but it did not work!

what have i missed?

thanks
>
> --
> Micah J. Cowan
> http://micah.cowan.name/
>



-- 
%>>> "".join( [ {'*':'@','^':'.'}.get(c,None) or
chr(97+(ord(c)-83)%26) for c in ",adym,*)&uzq^zqf" ] )




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