Re: [Discuss-gnuradio] what does noutput mean in a FFT block whic fft_len=2048?

[Marcus Müller]

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Hi BZS,
you're mixing concepts here: the FFT len is your FFT size, but noutput
is the number of items you are allowed to produce (maximum).
Please re-read the writing an out-of-tree module wiki page to
understand the difference better :)

Greetings,
Marcus

On 10.03.2014 03:21, ??????? wrote:
> hi, i want deal the data after FFT in my own block,i  copy a
> fft_len*sizeof(gr_complex) length of data from in to a buffer,then
> deal the data ,and  copy the dealed data from buffer to the out, in
> a FFT blocks,if there is size_t
> block_size=output_signature()->sizeof_stream_item(0); when i use
> memcpy(out,in,block_size*noutput ); it works normally , but when i
> do it like this :memcpy(out,in, fft_len*sizeof(gr_complex) );,it
> does not work
> 
> 
> does the result of block_size*noutput  have any relations with
> fft_len*sizeof(gr_complex) or some other suggestions thanks, BZS
> 
> 
> 
> _______________________________________________ Discuss-gnuradio
> mailing list address@hidden 
> https://lists.gnu.org/mailman/listinfo/discuss-gnuradio
> 
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