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Subject: |
`copy-tree' of a vector copy sharing structure.with original |
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Date: |
Thu, 23 Sep 2010 01:28:33 -0400 |
When copy-tree copies vectors the copy shares structure with the original.
This is unlike the behavior of copy-tree on a list of lists:
(let ((orig '((a b) (c d) (e f) (g h)))
new-cp)
(setq new-cp (copy-tree orig))
(equal (elt
(prog1 orig
(setf (car new-cp) "bubba")) 0)
'(a b)))
;=> t
(let ((orig [[a b] [c d] [e f] [g h]])
new-cp)
(setq new-cp (copy-tree orig))
(string-equal (aref (prog1 orig
(aset new-cp 0 "bubba"))
0)
"bubba"))
;=> t
Shouldn't idx 0 of the orig tree still be [a b]?
Note This bug _should_ prob. have stayed with Bug7083 but that bug
report was prematurely closed.
--
/s_P\
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--- Begin Message ---
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Subject: |
Re: bug#7088: `copy-tree' of a vector copy sharing structure.with original |
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Date: |
Thu, 23 Sep 2010 10:47:36 +0200 |
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User-agent: |
Gnus/5.13 (Gnus v5.13) Emacs/23.2 (gnu/linux) |
MON KEY <address@hidden> writes:
> When copy-tree copies vectors the copy shares structure with the original.
Works as documented. A vector is not a cons cell.
If TREE is a cons cell, this recursively copies both its car and its cdr.
^^^^^^^^^
Andreas.
--
Andreas Schwab, address@hidden
GPG Key fingerprint = 58CA 54C7 6D53 942B 1756 01D3 44D5 214B 8276 4ED5
"And now for something completely different."
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