Re: query-replace-regexp-eval is quite nice, but...

[Ehud Karni]

on
        Mon, 02 Feb 2004 11:24:34 +0100)
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On Mon, 02 Feb 2004 11:24:34 +0100, Andreas Schwab <address@hidden> wrote:
>
> David Kastrup <address@hidden> writes:
>
> [snip]
> >
> > So the idea is to build your replacement string with Lisp, and this
> > is quite an excellent thing.  It is completely defeated because the
> > replacement is then done non-literally.  Which means that if \0
> > would have matched \footnote, replacing the string just with \0 (which
> > one would expect to do nothing in effect) will barf because the
> > regexp replacer will not know what \f is supposed to be.
>
> I agree this is a bug.
>
> > Is there anybody that would make a case for a non-literal
> > replacement?  If not, is there anybody with enough of a clue to find
> > out how to fix this?  I have taken a look at perform-replace, but it
> > does not seem to offer an option for literal replacement for
> > regexps.  Should we add one?
>
> Currently, perform-replace uses literal replacement for all non-regexp
> searches, and non-literal otherwise.  What we could do is offer a special
> version of match-string that quotes backslashes and use that in
> replace-match-string-symbols.

How about checking regexp-flag (which is bound by `perform-replace') ?

Assuming your "literal" result string (containing \n) is STR you can
add something like this to your lisp:

       (if regexp-flag
           (regexp-quote STR)
           STR)

Ehud.


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