What happens when I evaluate the call the second time?

[Eric Lilja]

Hello, I've just started with lisp programming and I encountered 
something I thought was odd.

Using GNU Emacs 22.0.990.1 (i386-mingw-nt5.1.2600) of 2007-06-02 on 
MINDCOOLER

Starting with -Q

In the scratch buffer I write

(defun average (x y)
  (/ (+ x y) 2)
)

(average 2 3)

First C-x C-e after the function, then twice after calling it. The 
output is:
average
2
2 (#o2, #x2, ?\C-b)

Now what's the (#o2, #x2, ?\C-b) stuff?

- Eric

PS. I notice that the output is 2 and not 2.5, I guess the output gets 
truncated to an integer (the decimal part is discarded).