Re: Using `call-process-shell-command' in `process-lines'

[Lennart Borgman (gmail)]

Eli Zaretskii wrote:
> > Date: Mon, 26 Nov 2007 22:08:17 +0100
> > From: "Lennart Borgman (gmail)" <address@hidden>
> > CC: address@hidden, address@hidden, address@hidden
> >
> > > >    (apply #'call-process "find.exe" nil
> > > >           (get-buffer-create "output")
> > > >           nil
> > > >           (list "c:/emacs-lisp/old/" "-name"
> > > >                 (shell-quote-argument "*.el" )))
> > > Yes, sorry; I tried to correct myself in another message.
> > >
> > > > but it does not work AFAICS.
> > > ??? It does for me.
> > It doesn't for me
>
> Please describe how it fails.

  (apply #'call-process "find.exe" nil
         (get-buffer-create "output")
         nil
         (list "c:/emacs-lisp/old/"
               "-name"
               (shell-quote-argument "*.el" )
               ))

gives nothing in the "output" buffer and returns 0.

  (apply #'call-process "find.exe" nil
         (get-buffer-create "output")
         nil
         (list "c:/emacs-lisp/old/"
               "-name"
               "m*.el"
               ))

gives the correct output and returns 0.

  (apply #'call-process "find.exe" nil
         (get-buffer-create "output")
         nil
         (list "c:/emacs-lisp/old/"
               "-name"
               "*.el"
               ))

gives the error "paths must precede expressions" and returns 1.

  (apply #'call-process "find.exe" nil
         (get-buffer-create "output")
         nil
         (list "c:/emacs-lisp/old/"
               (shell-quote-argument "-name")
               (shell-quote-argument "*.el" )
               ))

matches all files (not only *.el) and returns 1.