Re: Why is not end-of-defun-function buffer local?

[Stefan Monnier]

>> The "automatically local when set" is of course making it yet
>> a bit messier.  Not sure what we should do about that.

> I'm still missing you.  Consider

> (defvar foo 0)

> (let ((this-buffer (current-buffer)))
>   (set (make-local-variable 'foo) 1)
>   (let ((foo 2))
>     (with-temp-buffer "*foo*"
>       (let ((foo 3))
>       (with-current-buffer this-buffer
>         foo)))))

> Doesn't this exhibit the same "deep binding" behavior as
> `make-variable-buffer-local'?

Of course.  It's just a bit less surprising because you then only see it
when you explicitly ask to make-local-variable.


        Stefan