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Re: emacs lisp syntax rfc: (cond (EXPR => (lambda (X) ...)))
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From: |
Andy Wingo |
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Subject: |
Re: emacs lisp syntax rfc: (cond (EXPR => (lambda (X) ...))) |
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Date: |
Tue, 11 Jan 2011 09:20:38 -0800 |
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User-agent: |
Gnus/5.13 (Gnus v5.13) Emacs/23.2 (gnu/linux) |
On Wed 05 Jan 2011 15:36, Richard Stallman <address@hidden> writes:
> I should clarify. The original proposal should read:
>
> (cond (EXPR => 1-ARY-FUNC) ...)
>
> It would rarely be useful, so it is not worth adding to Emacs Lisp.
It exists in Scheme FWIW, and is widely used there. (Probably doesn't
have much bearing on this argument, though.)
Andy
--
http://wingolog.org/
- Re: emacs lisp syntax rfc: (cond (EXPR => (lambda (X) ...))), (continued)
- Re: emacs lisp syntax rfc: (cond (EXPR => (lambda (X) ...))), Stefan Monnier, 2011/01/05
- Re: emacs lisp syntax rfc: (cond (EXPR => (lambda (X) ...))), Harald Hanche-Olsen, 2011/01/05
- Re: emacs lisp syntax rfc: (cond (EXPR => (lambda (X) ...))), Stefan Monnier, 2011/01/05
- Re: emacs lisp syntax rfc: (cond (EXPR => (lambda (X) ...))), Helmut Eller, 2011/01/06
- Re: emacs lisp syntax rfc: (cond (EXPR => (lambda (X) ...))), Stefan Monnier, 2011/01/06
- Re: emacs lisp syntax rfc: (cond (EXPR => (lambda (X) ...))), Richard Stallman, 2011/01/06
- Re: emacs lisp syntax rfc: (cond (EXPR => (lambda (X) ...))), Richard Stallman, 2011/01/05
- Re: emacs lisp syntax rfc: (cond (EXPR => (lambda (X) ...))),
Andy Wingo <=
Re: emacs lisp syntax rfc: (cond (EXPR => (lambda (X) ...))), Miles Bader, 2011/01/05
Re: emacs lisp syntax rfc: (cond (EXPR => (lambda (X) ...))), MON KEY, 2011/01/03