Re: User-defined record types

[Lars Brinkhoff]

> If you pass (:named foo) to cl-defstruct, foo will be put in list or
> vector slot 0, so I suppose that should work for records too.
>
> If you don't use the :named option, it seems there will be no type
> information in the instances.

I see now this is wrong, and there are more cases to consider.
This is the situation as of now:

- If you don't pass the :type option to cl-defstruct, you get a
cl-struct-FOO type tag in slot 0.

- If you pass :type but not :named, you don't get any type tag.

- If you pass :type and :named, you get a type tag in slot 0, which is
the same symbol as the struct name.