Re: User-defined record types

[Stefan Monnier]

>> If you pass (:named foo) to cl-defstruct, foo will be put in list or
>> vector slot 0, so I suppose that should work for records too.
>> If you don't use the :named option, it seems there will be no type
>> information in the instances.
> I see now this is wrong, and there are more cases to consider.
> This is the situation as of now:
> - If you don't pass the :type option to cl-defstruct, you get a
> cl-struct-FOO type tag in slot 0.

That's right.  And this symbol's value is the class object.
The same holds for EIEIO.

These are the main candidates for use of the new `record` type.

> - If you pass :type but not :named, you don't get any type tag.

And those should not use `record` but `vector` or `list`
depending on the :type that was specified.

> - If you pass :type and :named, you get a type tag in slot 0, which is
> the same symbol as the struct name.

But again, these shouldn't use `record`.


        Stefan