[Gnu-regexp-discuss] regexec() problem

[hi_biswanath]

 I am using <regex.h>.
 I have
 string _text = "This is the way to go.";                                       
                                       
  string _findRegexp = "\\s+";
  string _replaceRegexp = " ";
bool _caseSensitive = true;
  bool _globalReplace = true;
 int _flags = REG_EXTENDED;
  int _executionFlags = 0;
  if (!_caseSensitive) {_flags = _flags | REG_ICASE;}                        
  regex_t _compiledRE;
  regmatch_t *_reMatchesPtr = 0;
                                       
  long _result = regcomp(&_compiledRE, _findRegexp.c_str(), _flags);
  long _subexpressionCount = _compiledRE.re_nsub;
  _reMatchesPtr = new regmatch_t[_subexpressionCount+1];
_result = regexec(&_compiledRE,
                        _text.data(),
                        _subexpressionCount + 1,
                        _reMatchesPtr,
                        _executionFlags);
 Now, regexec() is in a loop to find and replace. And for the part 'go.' in 
_text, regexec() returns 0 in gcc 2.96 and 1 in gcc 3.3.2.

 Can someone please help?
 I am clueless.
 I will be very grateful for some help.

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