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Re: [Grammatica-users] Trying to disambiguate a grammar


From: Per Cederberg
Subject: Re: [Grammatica-users] Trying to disambiguate a grammar
Date: Sun, 18 Feb 2007 08:55:17 +0100
User-agent: Thunderbird 1.5.0.9 (Macintosh/20061207)

Hi Craig,

Most of the grammar below lends itself well to
tokenization with regular expressions. Consider
the following tokens:

BIN_NUMBER           = <<0(B|b)[0-1]+>>
OCT_NUMBER           = <<0[0-7]*>>
DEC_NUMBER           = <<[1-9][0-9]*>>
HEX_NUMBER           = <<0(x|X)[0-9A-Fa-f]+>>
MINUS                = "~"
DOT                  = "."
E                    = <<(e|E)>>

With the help of these you can rewrite the rest of
the grammar:

Int         = ["~"] NumberToken ;
NumberToken = BIN_NUMBER
            | OCT_NUMBER
            | DEC_NUMBER
            | HEX_NUMBER ;
Float       = ["~"] DEC_NUMBER "." [DEC_NUMBER] [Exponent] ;
Exponent    = E ["~"] DEC_NUMBER

If you are working to expand this into a full
programming language grammar, you'll run into
issues with the E token. As the tokenizer is
not context sensitive, it will always return
the longest matching token.

Also, I many grammars the definition of float
and integer decimal number are both built into
the same DEC_NUMBER token. For a full language
that is probably the better solution, leaving
some validation controls to the analyzer stage.
Here I opted for something more similar to your
original grammar.

Cheers,

/Per

Craig Ugoretz wrote:
Hello,
I am new to grammatica (and parsers in general) and I have a grammar that I am trying to disambiguate. Can anyone lend any advice? Hopefully, this should get me on the right track with the rest of my work... I apologize for the notation - it is EBNF, but nonstandard (and non-grammatica). <int> ::= ['~'] <nzdigit> { <digit> }
         |  ['~'] O { <octdigit> }+
         |  ['~'] ('0x' | '0X') { <hexdigit> }+
         |  ['~'] ('0b' | '0B') { <bindigit> }+
<float> ::= ['~'] { <digit> }+ '.' { <digit> } { ('e' | 'E') ['~'] { <digit> }+
<digit> ::= 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9
<nzdigit> ::= 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9
<octdigit> ::= 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7
<hexdigit> ::= <digit> | 'a' | 'b' | 'c' | 'd' | 'e' | 'f' | 'A' | 'B' | 'C' | 'D' | 'E' | 'F'
<bindigit> ::= 0 | 1
Can proper tokenization alone with regular expressions lend itself to disambiguating the grammar? This was a tactic that I tried, but was not familar enough with regular expressions to make progress.


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