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where is #<primitive-procedure apply>?
From: |
Paul Jarc |
Subject: |
where is #<primitive-procedure apply>? |
Date: |
Fri, 31 Jan 2003 20:11:31 -0500 |
User-agent: |
Gnus/5.090015 (Oort Gnus v0.15) Emacs/21.2 (i686-pc-linux-gnu) |
I have a lazy-catch handler that examines the stack to see what
procedure threw the exception, and what its arguments are. In the
case of the system-error resulting from this:
(apply execlp '("doenotexist" "doesnotexist"))
the procedure is #<primitive-procedure apply>, and the arguments are:
(#<primitive-procedure execlp> ("doenotexist" "doesnotexist"))
When this happens, I want to pretend the procedure was
#<primitive-procedure execlp> and the arguments were ("doenotexist"
"doesnotexist"). But how can I recognize this situation? This
doesn't work: (eq? apply (frame-procedure frame)) because apply is
#<procedure apply>, not #<primitive-procedure apply>. Is there some
way I can get a reference to #<primitive-procedure apply> to plug into
the comparison? I could deliberately trigger an error and save the
reference from the stack, but I'd like to know if there's a cleaner
way.
paul
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