Re: Ediff from command line - winXP

[Søren "Pengman" Pedersen]

> You coud use the emacs function expand-file-name:
>   expand-file-name is a built-in function.
>   (expand-file-name NAME &optional DEFAULT-DIRECTORY)
>
>   Convert filename NAME to absolute, and canonicalize it.
>   Second arg DEFAULT-DIRECTORY is directory to start with if NAME is
relative
>    (does not start with slash); if DEFAULT-DIRECTORY is nil or missing,
>   the current buffer's value of default-directory is used.
>   File name components that are `.' are removed, and
>   so are file name components followed by `..', along with the `..'
itself;
>   note that these simplifications are done without checking the resulting
>   file names in the file system.
>   An initial `~/' expands to your home directory.
>   An initial `~USER/' expands to USER's home directory.
>   See also the function `substitute-in-file-name'.
>
> gnudoit "(ediff (expand-file-name \"%2\" \"%1\") (expand-file-name \"%3\"
\"%1\"))"
>
> Then you call the batch file with the full directory path (don't know
> how to get this) and the two file names.


Thanx - That war just what I needed