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Are nested defun's byte-compiled?
From: |
Drew Adams |
Subject: |
Are nested defun's byte-compiled? |
Date: |
Sun, 15 May 2005 15:47:51 -0700 |
Is the code defining a nested defun byte-compiled when its enclosing defun
is compiled? Example source file foo.el:
(defcustom define-bar-flag t "Define `bar' if non-nil.")
(defun foo ()
"Do foo stuff. Define `bar' if `define-bar-flag' is non-nil."
(when define-bar-flag (defun bar () (bar-stuff)))
(rest-of-foo-stuff))
Suppose foo.el is byte-compiled, and then foo.elc is loaded.
Is `define-bar-flag' eval'd when compiling foo? I assume not. I assume that
`bar' is not defined if `define-bar-flag' was set to nil before foo.elc is
loaded. I assume that `bar' is not defined until `(foo)' is executed, and
then only if `define-bar-flag' is non-nil.
When foo.el was byte-compiled, is bar's potential definition (the defun
itself) also byte-compiled or not? That is, if `(foo)' is executed after
loading foo.elc, which version of `bar' is defined, byte-compiled or not?
If the answer is that the non-compiled version of `bar' is defined, how can
the code be changed to make the compiled version be defined instead? Is this
a good way to do that?
(defun foo ()
(when define-bar-flag (byte-compile (defun bar () (bar-stuff))))
(rest-of-foo-stuff))
- Are nested defun's byte-compiled?,
Drew Adams <=