Re: editing binary (hexa) data

[Peter Dyballa]

Am 17.05.2007 um 19:24 schrieb David Kastrup:

> You mean
>
>         M-x replace-regexp RET . RET \,(string-to-char \1)  RET

No, I meant that the text is first written in ASCII as "text" and  
then converted to ASCII values separated by spaces, i.e. the numbers  
and spaces we've seen.

> (returns Emacs' internal coding, not unicode or latin-1).

So it is not converting "ASCII" characters to their values?

> > or such and back with
> >
> >         M-x replace-regexp RET \([1-9][0-9]\)  RET \,(string (+ ?a \1)) RET
>
>         M-x replace-regexp RET [0-9]+  RET \,(string (+ ?a \#&)) RET
>
> But why ?a?  Weird.

You're right: this is nonsense! The numbers already *are* the ASCII  
values (and not the first, second, third ... letter, and the smallest  
letter is, of course, capital A!), so it's not necessary to add the  
smallest letter's ASCII value to the supposed ordinal. And two digits  
are not enough for all ASCII characters, since d already has 100 in  
decimal!

Why are you using ``\#&´´? Isn't \# meaning the back-reference?

--
Mit friedvollen Grüßen

  Pete

A child of five could understand this!  Fetch me a child of five.