Thierry Volpiatto schrieb:
Florian Beck <abstraktion@t-online.de> writes:
Marc Tfardy <m-t-o___CUT__IT@web.de> writes:
Marc Tfardy schrieb:
I try with:
(member '(2) '((1) (2) (3) (4)))
`member' tests the components: ›2‹ ist always equal (in the sense of
»eq«) to ›2‹
Compare:
(memq '(2) '((1) (2) (3) (4)))
(eq 2 2)
(eq '(2) '(2))
and this gives a expectet results ((2) (3) (4)), but:
(find '(2) '((1) (2) (3) (4)))
or
(position '(2) '((1) (2) (3) (4)))
returns nil. Why?
Because the first and the second »(2)« have the same components but are
*different* lists.
But this works:
(position '(2) '((1) (2) (3) (4)) :test (lambda (x y) (eq (car x) (car
y))))
position default test is 'eq, try 'equal
Thanks! It works with equal. But I have another problem.
find (and find-if) returns only first match. Is there another
function that returns all matched elements. Some example:
(find-if-all (lambda (x) (if (eq (nth 2 x) 'byte) t nil)) '((1.1 "x"
int) (2.2 "y" byte) (3.3 "q" int) (4.4 "b" byte) (5.5 "a" float)))
should returns:
((2.2 "y" byte) (4.4 "b" byte))
I found in cl-*.el nothing like this. Any hints?