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Re: How to see that a variable holds t
From: |
Lennart Borgman |
Subject: |
Re: How to see that a variable holds t |
Date: |
Sun, 3 Jan 2010 21:32:37 +0100 |
On Sun, Jan 3, 2010 at 6:11 PM, Cecil Westerhof <Cecil@decebal.nl> wrote:
> At the moment I have the following function:
> (defun switch-gnus-idle-daemon-do-log ()
> (interactive)
> (setq gnus-idle-daemon-do-log
> (case gnus-idle-daemon-do-log
> (10 t)
> (otherwise 10)))
> (message "gnus-idle-daemon-do-log: %s" gnus-idle-daemon-do-log))
>
> I know that it looks like overkill a case for switching to two values,
> but I expect that in the future there will be more values.
>
> What I really would like is;
> (defun switch-gnus-idle-daemon-do-log ()
> (interactive)
> (setq gnus-idle-daemon-do-log
> (case gnus-idle-daemon-do-log
> (t 10)
> (otherwise t)))
> (message "gnus-idle-daemon-do-log: %s" gnus-idle-daemon-do-log))
>
> Because I would like the default to be t and not 10. (For when the value
> is not one of the defined values.) But when I do this, it is always set
> to 10, because the case does not make a difference between t and 10. How
> do I solve this?
Doesn't this work:
(let ((T t))
(case T
((eq T t) (message "was t!"))
(t (message "T=%S" T))))