Can free variable refers to a lexical environment?

[IWAKI Hidekazu]

Hello,

I need to make a table factory function in emacs with cl extension.
but I'm scheme user. I'm confusing emacs lisp behavior.
will you please tell me the emacs lisp's free variable issue.

my table factory function is following code:
 (defun mk-table-instance ()
  (let ((table nil)) ;; create a lexical value `table`
    (defun __temp__ (msg &rest value)
      ;; some operation changes the lexical variable `table`
      (case msg
        ((push) (push (car value) table))
        (otherwise table)))
    (function __temp__)))
;; return the `__temp__`  procedure with the lexical variable `table`
;; i.e. return a closure.

(fset 'table-object (mk-table-instance))
;; 'table-object is an unique procedure object.
(table-object 'push 13)
;; my plan => operate an unique `table` variable which was created by
involving `mk-table-instance`
;; real        => "Debugger entered--Lisp error: (void-variable
table)"!!!!!!!

I researched this code. I guess the lexical binded variable `table` in
`mk-table-instance` procedure refer to the global environment.
In scheme, the variable refer to the lexical environment.

How to refer to a lexical environment?