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RE: print out all members of a list, v.1.0
From: |
Drew Adams |
Subject: |
RE: print out all members of a list, v.1.0 |
Date: |
Thu, 3 Mar 2011 20:09:02 -0800 |
> Emacs Lisp is mostly a reimplementation of MockLisp, the dialect that
> was used in Gosling Emacs, which was the original inspiration for GNU
> Emacs. It's also very much like MACLISP, the dialect that
> RMS had been using for over a decade.
>
> So he didn't design his own language, he was basically sticking with
> what he knew and liked.
Hm. Not to disagree too much, but on one point in particular: MockLisp was not
in any sense a dialect of Lisp - it was not Lisp at all. It only had some of
the appearance of Lisp (parenthesized expressions), none of the behavior.
- Re: print out all members of a list, v.1.0, Pascal J. Bourguignon, 2011/03/01
- Re: print out all members of a list, v.1.0, rusi, 2011/03/01
- Re: print out all members of a list, v.1.0, Barry Margolin, 2011/03/02
- Re: print out all members of a list, v.1.0, rusi, 2011/03/02
- Re: print out all members of a list, v.1.0, Pascal J. Bourguignon, 2011/03/02
- Re: print out all members of a list, v.1.0, Barry Margolin, 2011/03/02
- Re: print out all members of a list, v.1.0, Pascal J. Bourguignon, 2011/03/03
- Re: print out all members of a list, v.1.0, rusi, 2011/03/03
- Re: print out all members of a list, v.1.0, Pascal J. Bourguignon, 2011/03/03
- Re: print out all members of a list, v.1.0, Barry Margolin, 2011/03/03
- RE: print out all members of a list, v.1.0,
Drew Adams <=
- Re: print out all members of a list, v.1.0, Pascal J. Bourguignon, 2011/03/04
- Re: print out all members of a list, v.1.0, David Kastrup, 2011/03/04
- Re: print out all members of a list, v.1.0, Barry Margolin, 2011/03/04