Re: error in replace-match: "args out of range"

[ken]

On 04/04/2011 06:21 PM Tim X wrote:
> ken <gebser@mousecar.com> writes:
> 
>> On 04/03/2011 07:19 PM PJ Weisberg wrote:
>>> On 4/3/11, ken <gebser@mousecar.com> wrote:
>>>> On 03/28/2011 04:32 PM Stefan Monnier wrote:
>>>>> I'm just saying that
>>>>>
>>>>> M-: (some-regexp-search) RET
>>>>> M-: (replace-match ...) RET
>>>>>
>>>>> won't always do what you want, because a whole lot of code will run
>>>>> between the two.
>>>>>
>>>>>
>>>>>         Stefan
>>>> 
>>....
>>
>> So, yes, the search and replace-match are in the same function.  Are
>> they "close together"?  I'd say yes, but that's a judgment call really.
>>  The string I want to replace in this particular instance is a null string.
>>
> 
> Providing the code alway helps. While Stephan's points are valid and a
> common error people make, I don't think it is the problem you are
> seeing.

Yes, providing the actual code is generally a good idea... it gives
everyone something concrete to look at.  But the function I was writing
was too long to expect anyone to read and digest it in just a few
minutes; it would also require a lot of explanation from me to help
others to understand it; three or four ancillary functions play roles
and so they would have to be included also; all of this required a
specific kind of text file to work it on, so I would have need to
include that also; and besides all this, the code was a very unappealing
mess to look at, with all kinds of cruft commented out, sundry comments
inserted here and there, and some code not formatted in the traditional
fashion.  In short, it would have been too much work for everyone.  So I
thought just posting the directly relevant code fragments would be more
effective.  When there's a working package, a version 0.0001, I'll post
it on the web so anyone who's curious or wants to use it can do so.


> 
> It would help to see the regexp you are using to test this. Note that
> match-string returns nil if the subexpression you are asking for did not
> exist. If the subexpression did not exist, what would replace-match
> replace as there is no match?

Tim, this is a valid point generally, but not in this instance.  The
code included conditionals for each search and so if the search failed
to find the sought RE, a different block of code would be executed.  And
there was a block of code to cover each of the five possible conditions.


> 
> Note also, you can get rid of some of those progns i.e.
> 
>      (when (re-search-forward aname-re-str head-text-end-pt t)
>         (setq aname-str (match-string 2))
>         (setq head-text-nested (match-string 4))
>         (when (string= head-text-nested "")
>               (setq head-text-nested (create-heading-text))
>                 (if (not (string= aname-str ""))
>                    (replace-match head-text-nested t t nil 4)
>                   (setq aname-str (create-aname head-text-nested))
>                 (replace-match head-text-nested t nil nil 4)
>                 (replace-match aname-str t nil nil 2))))
> 
> Note that the 'else' part of an if form has an implicit progn, so by
> revesing the condition test, we can eliminate that progn. The 'unless'
> form can be used instead of 'when' if you want to reverse the logic of
> what you are doing. 

Yeah, inverting the conditionals does remove the progn statements and
makes the code shorter.  I read quite a bit about conditionals in some
of the docs... and someone here on this list explained about progn a bit
for me also.  But I wrote the code how I was thinking through the
problem, much in the way Kernighan and Ritchie say happens naturally...
I think it was in the "Introduction" to their book, "The C Programming
Language".  That "progn" statement does seem clunky... it took some
getting used to using an entire word just to denote the beginning of a
block of text.  But I've adapted.  In fact, now it's like a huge flag
telling me, 'this is where the block of text begins which executes when
the if statement above is true.'  It makes it easier to find those if's
 too.  Sometimes I almost wish there was a corresponding "<progn" to
just as boldly show me where the end of the code block is.  But it's too
late to design the syntax for lisp :) and I'd probably get tired of
"<progn" after a time anyway.


> 
> (Note above is untested, but intention should be clear)
> 
> My guess is that it does not work because replace-match has no idea what
> it is yhou want to match as the subexpression was not found i.e. is not
> in the string, so it has no way to know where in the string to do the
> replace.

When the subexpression isn't found, then the search fails.  When the
search fails, then a different code block executes, one which doesn't
require the existence of that subexpression.

In addition, I wrote a simple diagnostic function (a couple versions of
it actually) to show me what, if anything, was matched and inserted this
function at various points in the code.  This confirmed that the
searches and conditionals were functioning as I wanted.  Something else
was wiping out the subexpressions.  I eventually traced the problem to
the read-from-minibuffer function.  For some reason it wipes out
previously established subexpressions.  I wasn't expecting that at all.


> 
> Tim

Tim, thanks for all the input... and everyone else too.  Don't worry...
there's quite a bit more code I need to write, so I'll most likely be
posting more questions/problems in the upcoming.  (Is that something
anybody's worried about? :)  )