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Re: parsing a date


From: ken
Subject: Re: parsing a date
Date: Sun, 23 Dec 2012 22:54:57 -0500
User-agent: Mozilla/5.0 (X11; Linux i686; rv:10.0.11) Gecko/20121120 Thunderbird/10.0.11

On 12/23/2012 10:02 PM Eric Abrahamsen wrote:
ken<gebser@mousecar.com>  writes:
....

--8<---------------cut here---------------start------------->8---
(defun ddd (s)
   (format-time-string "%Y/%m/%d"
     (apply 'encode-time 0 0 0
       (nthcdr 3 (parse-time-string
                 (replace-regexp-in-string "\.tail" "" s))))))
--8<---------------cut here---------------end--------------->8---

That works.  Thanks much.





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