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Re: About equality in Emacs
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From: |
Xue Fuqiao |
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Subject: |
Re: About equality in Emacs |
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Date: |
Mon, 4 Feb 2013 08:20:01 +0800 |
On Sun, 03 Feb 2013 12:00:44 -0500
Pascal J. Bourguignon wrote:
> Perhaps. But in Common Lisp, it would be EQL, since (eq 1 1) or (eq #\a
> #\a) can return NIL. (member 1 '(1 2 3) :test (function eq)) is not
> conforming in Common Lisp.
Thanks for your reply, it is a bug and it will be fixed in GNU Emacs 24.2.93.
BTW, What does `#\a' mean?
--
Best regards, Xue Fuqiao.
http://www.emacswiki.org/emacs/XueFuqiao