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Re: Another replace regexp with list question
From: |
WJ |
Subject: |
Re: Another replace regexp with list question |
Date: |
5 Nov 2013 00:21:36 GMT |
User-agent: |
XanaNews/1.18.1.6 |
Barry Margolin wrote:
> In article <mailman.1310.1370826222.22516.help-gnu-emacs@gnu.org>,
> Leandro Marcolino <leandromarcolino@gmail.com> wrote:
>
> > Hello, everyone!..
> >
> > This time I am trying to find occurrences of:
> >
> > "<span style='color:white'>私私私私</span>", but
> > the number of 私 can change from 1 to many.
> >
> > And I want to replace each 私 of the list to a white space (besides
> > removing the <span> clause). So, if there were x "私", I need x " ".
> > Is it possible to do this using replace-regexp?.. Of course I can't just
> > look for "私" and replace to " ", because I have occurrences of
> > "私" that are not inside the group "<span
> > style='color:white'></span>".
> >
> > I tried something like "<span style='color:white'>\(\(私\)+\)</span>
> > -> \,(cond (\1 " ")))", but then I lose the information of how many
> > "私" were there, and everything changes to a single " "....
> >
> > Thanks for your help!.. :)
> >
> > Regards,
> > Leandro
>
> Regular expressions can't count.
>
> I would do it with a keyboard macro. Search for the span, mark it as a
> region, narrow to region, use replace-string to replace each 私
> with space, widen.
(replace-regexp-in-string
"<span>\\(私\\)+</span>"
(lambda (s)
(make-string
(length (replace-regexp-in-string "[^&]" "" s))
? ))
"私 hi<span>私私</span>there 私")
===>
"私 hi there 私"
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