Re: How to translate `rx' expressions to `rx-to-string'?

[Thorsten Jolitz]

Nicolas Richard <theonewiththeevillook@yahoo.fr> writes:

> Thorsten Jolitz <tjolitz@gmail.com> writes:
>> Seems I did not get the syntax for function rx-to-string yet - any hints
>> would be welcome.
>
> Read the code of rx.
>
> (format "%S" (rx bol "foo_" (+ word) eol))
> => "\"^foo_[[:word:]]+$\""
>
> (format "%S" (rx-to-string '(and bol "foo_" (+ word) eol) t))
> => "\"^foo_[[:word:]]+$\""
>
> HTH,

Yes, that helps, thank you!

OTOH, just a bit more info and maybe one little example in the docstring
of `rx-to-string' would help a lot. This is supposed to be easier to use
than regular regexp syntax ...

-- 
cheers,
Thorsten