RE: using lisp in replacement string

[ronaldo.mercado]

Hello, the function below performs a global search-replace

(defun hh ()
  (interactive)
  (let (match-beginning match-end match-string replacement)
    (goto-char (point-min))
    (while (re-search-forward "|\\([^|]*\\)|"  nil t)
      (setq match-beginning (match-beginning 0))
      (setq match-end (match-end 0))
      (setq replacement (concat "|" (calc-eval (match-string 1)) "|") )
      (goto-char match-beginning)
      (re-search-forward "|\\([^|]*\\)|" match-end nil)
      (replace-match replacement t t nil 0))))

I did not understand why I needed to perform re-search-forward twice though. 
without the second search, results were garbled.

________________________________________
From: help-gnu-emacs-bounces+ronaldo.mercado=diamond.ac.uk@gnu.org 
[help-gnu-emacs-bounces+ronaldo.mercado=diamond.ac.uk@gnu.org] on behalf of 
Dmitry Gutov [dgutov@yandex.ru]
Sent: 24 December 2014 14:52
To: Guido Van Hoecke
Cc: help-gnu-emacs
Subject: Re: using lisp in replacement string

On 12/24/2014 04:40 PM, Guido Van Hoecke wrote:

> ​Not really, if you quote it, it replaces the formulas by the calc-eval
> expression :(

If you don't quote it, it's not a string.

Anyway, check out these lines from `replace-regexp' docstring:

"This function is for interactive use only;
in Lisp code use `re-search-forward' and `replace-match' instead."
...
"In interactive calls, the replacement text may contain `\,'"

You're not using it interactively.


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