help-gplusplus
[Top][All Lists]
Advanced

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

std::function with std::unique_ptr argument


From: Rodolfo Schulz de Lima
Subject: std::function with std::unique_ptr argument
Date: Thu, 04 Jun 2009 12:23:35 -0300
User-agent: Thunderbird 2.0.0.21 (X11/20090409)

Hi, I'm trying to use a std::function with std::unique_ptr arguments but
the std::function invocation ends up using std::unique_ptr copy ctor,
which is private/deleted.

Since std::function is a forward call wrapper, its operator() should
have forwarded properly its arguments to the wrapped function, but

M_invoker(_M_functor, __args...);

and

(*_Base::_M_get_pointer(__functor))(__args...);


doesn't seem to do that. IMHO it should be

_M_invoker(_M_functor, std::forward<_ArgTypes>(__args)...);

(*_Base::_M_get_pointer(__functor))(std::forward<_ArgTypes>(__args)...);


Any objections?

Regards,
Rodolfo Lima





reply via email to

[Prev in Thread] Current Thread [Next in Thread]