indexing structures

[John W. Eaton]

On  5-Feb-2004, Scott Skjei <address@hidden> wrote:

| I would like to create a number of data structures with a looping/indexing 
| command.  The idea I have is
| 
| for i = 1:n
|     structure(i).element = a(i,:)
| endfor
| 
| so each row i of the matrix a becomes an element of structure(i).
| 
| Any help would be greatly appreciated.

I don't know of a way to say this in Octave without using a loop, but
maybe someone else has an idea.

If you do use a loop, you will probably want to fill the structure in
reverse order, so that you don't resize it and copy the elements N
times:

  for i = n:-1:1
    structure(i).element = a(i,:);
  endfor

jwe



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