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Re: Right function for Discrete Convolution
From: |
NZG |
Subject: |
Re: Right function for Discrete Convolution |
Date: |
Tue, 8 Feb 2005 11:47:08 -0600 |
User-agent: |
KMail/1.7.1 |
> Convolution returns an output longer than its inputs by definition.
Does it? Perhaps I am misunderstanding convolution altogether.
I have always learned it from the control standpoint, as being
x(n)*y(n) =
the infinite summation of x(k)y(n-k) from k=-infy to k=infy for all n.
This would imply the same dimension, n, would it not?
Am I missing something?
Does anyone have any links that explain why the dimension changes?
thx,
NZG.
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