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Re: Why is 2/3 not seen as rational? [was "plotting even function"]


From: John B. Thoo
Subject: Re: Why is 2/3 not seen as rational? [was "plotting even function"]
Date: Tue, 22 Mar 2005 06:24:00 -0800

Henry, I'm glad that I could "contribute" to the list. :-D

Seriously, though, my BIG THANK YOU goes to everyone who participated (and to those who may still participate) in this discussion for helping me to understand this a little better. Clearly, numerics has subtleties (for me) for which I need to watch. I have learnt from everyone's exchanges.

Cheers.
---John.


On Mar 21, 2005, at 8:17 AM, Henry F. Mollet wrote:

WOW, I have to go back to school and learn about De Moivre's theorem to
understand why Octave does what it does. I had blindly believed what
Octave/Gnuplot was graphing. Had no idea what John Thoo's "simple" question
would lead to!
Henry

on 3/21/05 6:51 AM, Mike Miller at address@hidden wrote:

On Mon, 21 Mar 2005, Paul Kienzle wrote:

The cubed root function is multi-valued and Octave is choosing a
different root than you expect.  Look at -8 for example:

x^3 + 8 has three roots:

 octave> roots([1,0,0,8])
 ans =

 -2.0000 + 0.0000i
  1.0000 + 1.7321i
  1.0000 - 1.7321i

Octave chooses one of them:

 octave> (-8).^(1/3)
 ans = 1.0000 + 1.7321i


It seems to 'choose' using De Moivre's theorem.

For x > 0 and integer n != 0:

-x = x * (cos(pi) + sin(pi)*i)

(-x)^(1/n) = x^(1/n)*(cos(pi/n)+sin(pi/n)*i)

As someone else pointed out, the abs function will force the answer to be
a real integer:

- Mapping Function:  abs (Z)
    Compute the magnitude of Z, defined as |Z| = `sqrt (x^2 + y^2)'.

    For example,

         abs (3 + 4i)
              => 5

So, for x > 0 and integer n != 0,

-abs((-x)^(1/n))

seems to give the desired answer when n is odd, but that isn't very
helpful because -(x)^(1/n) gives the same answer when n is odd.

On the other hand, this seems to do what the guy originally wanted (for
scalar integer values of a and b and any real-valued x vector.):

abs(rem(a,2))*abs(rem(b,2))*sign(x).*(abs(x).^(a/b)) +
(1-abs(rem(a,2)))*abs(x).^(a/b) + abs(rem(a,2))*(1-abs(rem(b,2)))*x.^(a/b)

Mike



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