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Re: modulo 2 pi?
From: |
Francesco Potortì |
Subject: |
Re: modulo 2 pi? |
Date: |
Wed, 21 Jan 2009 14:23:38 +0100 |
>If I have two angles 'theta' and 'psi', and I want to compute their
>difference I can simply do
>
> d = theta - psi;
>
>However, I'd like this result to be in the range [0, 2*pi]. Can I simply
>do
>
> d = mod (theta - psi, 2*pi);
>
>or will this fail in some cases?
It should not. It would fail if you used 'rem', but using 'mod' you
should have no problems.
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- modulo 2 pi?, Søren Hauberg, 2009/01/21
- Re: modulo 2 pi?,
Francesco Potortì <=