Re: Need help with nelder_mead_min.m

[etienne]

  Hello,

something like

octave:408> function val = foo (xyz), val = sum (xyz .^ 2); endfunction
octave:409> help nelder_mead_min
[snip]
### Start nelder_mead_min() from a random point
octave:410> [xyz0, val0, nev] = nelder_mead_min ("foo", randn(1,3))
xyz0 =

   2.1237e-08   1.0243e-08  -4.4610e-09

val0 =  5.7582e-16
nev =  201
### Start nelder_mead_min() from the minimum
octave:411> [xyz0, val0, nev] = nelder_mead_min ("foo", [0 0 0])
xyz0 =

   0   0   0

val0 = 0
nev =  236

  Hth,

  Etienne

Quoting ???????? ???????
<address@hidden> (Mon, 23 Nov 2009 21:43:57 +0300):

> Hi all!
>
> I can't figure out how to work with this function. I will be very
> glad if one could explain the subject.
>
>
> For an example lets see the problem.
>
>
> function y = foo (x, y, z)
>     y = x**2 + y**2 + z**2;
> endfunction
>
>
> I need to find a minima of the foo in [-1;1]*[-1;1]*[-1;1] region.
> I know the answer, but how I must set up an options and arguments
> for nelder_mead_min.m?
>
>
> Best regards,
> Grigory 

--
http://www.isr.ist.utl.pt/~etienne

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