Re: compute all pairwise diffs

[Claudio Belotti]

On Fri, Jul 8, 2011 at 16:10, CdeMills <address@hidden> wrote:
> I wanted to look it the distance was not below some threshold. The call
> unique([1 1+eps])
> returns a set with two values, which doesn't make much sense in my case:
> such tiny difference may result from pure numerical error, and not from
> "real" data separation.

I see, then you can modify unique.m to suit your needs?
I suppose you just need to change

match = (y(1:n-1) == y(2:n));
into
match = (abs(y(1:n-1) - y(2:n))<=tolerance);
to find the differences within a given tolerance